How do you determine the amount of herbicide needed?

How do you determine the amount of herbicide needed?

• A. target area x labeled application rate
• B. target area / labeled application rate
• C. number of plants x water per plant
• D. area x pesticide weight per unit area

Answer: (A)

The amount of herbicide you need comes from multiplying the area you’ll treat by the rate the label calls for per that area. The label specifies how much product to use for a given area, such as ounces per 1,000 square feet or gallons per acre. By multiplying the area (in square feet or acres) by that rate, you get the total quantity to mix and apply. For example, if you’re treating 2,000 square feet and the label rate is 0.5 ounce per 1,000 square feet, you convert the area to units of 1,000 ft^2 (2,000 ÷ 1,000 = 2) and multiply by the rate: 2 × 0.5 oz = 1 oz of product to use. Label rates can also be given as volume per acre, in which case you convert the treated area to acres first and multiply by that rate. Dividing the area by the rate or using a per-plant calculation doesn’t yield the total amount to apply and isn’t how herbicides are dosed for area-wide treatments.

The amount of herbicide you need comes from multiplying the area you’ll treat by the rate the label calls for per that area. The label specifies how much product to use for a given area, such as ounces per 1,000 square feet or gallons per acre. By multiplying the area (in square feet or acres) by that rate, you get the total quantity to mix and apply.

For example, if you’re treating 2,000 square feet and the label rate is 0.5 ounce per 1,000 square feet, you convert the area to units of 1,000 ft^2 (2,000 ÷ 1,000 = 2) and multiply by the rate: 2 × 0.5 oz = 1 oz of product to use.

Label rates can also be given as volume per acre, in which case you convert the treated area to acres first and multiply by that rate.

Dividing the area by the rate or using a per-plant calculation doesn’t yield the total amount to apply and isn’t how herbicides are dosed for area-wide treatments.